ChantelleM
ChantelleM
12-04-2018
Mathematics
contestada
Can anyone help me solve for a, b, and c?
Respuesta :
gmany
gmany
05-07-2018
[tex]\sqrt{x^{12}y^9z^5}=\sqrt{x^{6\cdot2}y^{8+1}z^{4+1}}=\sqrt{(x^6)^2y^8yz^4z}\\\\=\sqrt{(x^6)^2}\cdot\sqrt{y^{4\cdot2}}\cdot\sqrt{z^{2\cdot2}}\cdot\sqrt{yz}=x^6\sqrt{(y^4)^2}\cdot\sqrt{(z^2)^2}\cdot\sqrt{yz}\\\\=\boxed{x^6y^4z^2\sqrt{yz}}[/tex]
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