khalfaoui1908 khalfaoui1908

10-02-2018
Physics

contestada

How much heat is required to warm 122 g of water by 23.0 c?

Respuesta :

summerlee1986p44ai3 summerlee1986p44ai3

20-02-2018

122 g * 4,186 (j/g*°c) * 23°c = 11745.916 j

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Uraniumdavid Uraniumdavid

06-11-2019

Answer: 11745.92 j

Explanation: using heat = mc∆

Where k is mass

C is heat capacity of water = 4.186 j/gc

∆ is temperature

H = 122 × 4.186 × 23

= 11745.92 j

Answer Link

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