Respuesta :

wikk
First, you must find the molar mass of HNO3.
H = 1.01
N = 14.01
O3 = 16 × 3 = 48
Molar mass ≈ 63.01 g/mol

46.21 gHNO3 × (1 molHNO3/63.01 gHNO3) × (6.022×10^23 moleculesHNO3/1 molHNO3) =
4.4 × 10^23 molecules HNO3

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