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40 metres.. Hope this helps u
Apocrophon
It's 40 ft.

Since the rocket is launched from a platform, then the height of the rocket at 0 seconds will be the height of the platform.
[tex] h(t)=-16t^{2}+70t+40\\h(t)=-16(0)^{2}+70(0)+40\\h(t)=0+0+40=40ft[/tex]

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