olution
Basically, the number of asymptotes will be the number of solutions the denominator of the function has
We are given the function
[tex]f(x)=\frac{5}{3x(x+1)(x-7)}[/tex]
Solving the denominator
[tex]\begin{gathered} 3x(x+1)(x-7)=0 \\ \\ x=0,-1,7 \end{gathered}[/tex]
he answer is 3 vertical asymptotes
