Answer:
[tex]\theta = 41^{\circ}[/tex]
Step-by-step explanation:
[tex]~~~~~~~\sin 49^{\circ} = \cos \theta\\\\\implies \theta = \cos^{-1}\left(\sin 49^{\circ} \right)\\\\\implies \theta = \cos^{-1} \left[\cos \left(90^{\circ} - 49 ^{\circ} \right) \right]\\\\\implies \theta= \cos^{-1}\left( \cos 41^{\circ} \right)\\\\\implies \theta = 41^{\circ}[/tex]
