golddeathninja02 golddeathninja02

11-05-2022
Mathematics

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loneguy loneguy

11-05-2022

[tex]\textbf{1)}\\\\\text{Diameter} = 2 \cdot \text{Radius} = 2 \times 9~ \text{in} = 18~ \text{in}.\\\\\textbf{2)}\\\\\text{Radius} = \dfrac{\text{Diameter}} 2 = \dfrac{12 ~ \text{in}} 2 = 6 ~ \text{in}[/tex]

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