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10-11-2021
Chemistry

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a hot air balloon has a volume of 875L. what is the original temperature of the balloon if its volume changes to 955 L when heated to 56

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aminaahmadsaeed87 aminaahmadsaeed87

14-11-2021

Answer:

using Charles law

v1/t1= v2/ t2

Explanation:

875/t1=955/56+273

t1= 329* 875/955

t1= 302.82k

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