Respuesta :

mhanifa

Answer:

  • h - any real number

Step-by-step explanation:

  • 3 (h−9) + 2h = h − 27 + 4h
  • 3h - 27 + 2h = 5h - 27
  • 5h - 27 = 5h - 27
  • 0 = 0

h = any number

[tex]\\ \sf\longmapsto 3(h-9)+2h=h-27+4h[/tex]

[tex]\\ \sf\longmapsto 3h-27+2h=5h-27[/tex]

[tex]\\ \sf\longmapsto 5h-27=5h-27[/tex]

[tex]\\ \sf\longmapsto 5h-5h=-27+27[/tex]

[tex]\\ \sf\longmapsto 0=0[/tex]

The expression has no solutions

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