iyannaspruill44 iyannaspruill44

11-11-2020
Mathematics

contestada

what methods could be used to solve the following quadratic equation x^2 +12-28=0

Respuesta :

virtuematane virtuematane

12-11-2020

Answer:

Step-by-step explanation:

x^2 +12x-28=0

x^2+(14-2)x-28=0

x^2+14x-2x-28=0

X(X+14)-2(X+14)=0

(X+14)(X-2) is the factor of this quadratic equation.

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