Respuesta :

luana
[tex]\frac{1}{3}(2b+9)=\frac{2}{3}(b+\frac{9}{2})\ \ \ \ | multiply\ by\ 3\\\\ 2b+9=b+\frac{9}{2}\ \ \ | multiply\ by\ 2\\\\ 4b+18=2b+9\ \ \ \ | subtract \ 2b\\\\ 2b+18=9\ \ \ \ | subtract\ 18\\\\ 2b=-9\ \ \ \ | divide\ by\ 2\\\\ b=-4,5[/tex]