VinoFranko VinoFranko
  • 11-07-2020
  • Mathematics
contestada

find the value of the geometric series
1000 + 1000(1.03) + 1000(1.03)2 + . . . + 1000(1.03)9​

Respuesta :

Alfpfeu
Alfpfeu Alfpfeu
  • 12-07-2020

Answer:

[tex]\boxed{\sf \ \ \ 11,464 \ \ \ }[/tex]

Step-by-step explanation:

hello

we need to compute the following

[tex]\sum\limits^9_{i=0} {1000(1.03)^i}=1000\dfrac{1.03^{10}-1}{1.03-1}=11463.879...[/tex]

hope this helps

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