Casgar
Casgar Casgar
  • 12-04-2020
  • Mathematics
contestada

Please... I really need to do this...
а) sin(2х + 3) = а + 4
б) 2cos(х + π/3) = а2 - 3а
в) tg22х - (2а +1)tg2х + а(а + 1) = 0.

Respuesta :

Kylanb125
Kylanb125 Kylanb125
  • 12-04-2020

Answer:

\sin (2x)-\sin (x)-2\cos (x)+1=0 ...... I did the best I could hope this helps

Step-by-step explanation:

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