Respuesta :

gmany

[tex]f(1)=3\\\\f(n)=[f(n-1)]\\\\f(2)=[f(2-1)]=[f(1)]=[3]=3\\\\f(3)=[f(3-1)]=[f(2)]=[3]=3\\\\f(4)=[f(4-1)]=[f(3)]=[3]=3\\\\f(5)=[f(5-1)]=[f(4)]=[3]=3[/tex]